. Δίδω τον κώδικαΚώδικας: Επιλογή όλων
\draw[line width=1.6pt] plot[smooth,domain=2.4:4.7] (\x, {1/(\x-2)});
\draw[line width=1.6pt] plot[smooth,domain=-4.7:-2.1] (\x, {1/(\x-2)});και ενώ ο δεξί κλάδος γίνεται , ο αριστερός κλάδος δε γίνεται. Δείτε π.χ
![\displaystyle{\begin{tikzpicture}
\draw[->] (-5, 0) -- (5, 0) node[below]{x};
\draw[->] (0, -3) -- (0, 3) node[left]{y};
\draw[line width=1.6pt] plot[smooth,domain=2.4:4.7] (\x, {1/(\x-2)});
\draw[line width=1.6pt] plot[smooth,domain=-4.7:-2.1] (\x, {1/(\x-2)});
\end{tikzpicture}}](/forum/ext/geomar/texintegr/latexrender/pictures/8002ad5c881ce3eb21e47ac67550680b.png "\displaystyle{\begin{tikzpicture}
\draw[->] (-5, 0) -- (5, 0) node[below]{x};
\draw[->] (0, -3) -- (0, 3) node[left]{y};
\draw[line width=1.6pt] plot[smooth,domain=2.4:4.7] (\x, {1/(\x-2)});
\draw[line width=1.6pt] plot[smooth,domain=-4.7:-2.1] (\x, {1/(\x-2)});
\end{tikzpicture}}")
Γιατί; Τι χάνω;
, όχι του 
. Δηλαδή να είναι π.χ. 